613 Oakland Ave, Austin, TX, 78703
Kees Vantilburg 2 Public Records Found
There are 2 people with the name Kees Vantilburg, aged 67 to 67, in the U.S. Kees Vantilburg's information, such as phone numbers, emails, and current and past addresses from 1 state, including Texas, have been found on Rew Online. Get access to Kees's birthdays, relatives, neighbors, associates, and property details to verify the right person. You may also find their criminal records, social media accounts, and other public data.
Kees Vantilburg, 67 Austin, TX
Resident Since: 2014Year Built: 1947Property Type: Single Family Dwelling UnitProperty Value: $460,000
Kees Vantilburg from Austin, TX, was born on May 14, 1959, and is now 67 years old. This person has been living at the property valued at $460,000 since 2014. The house was constructed in 1947. Kees Vantilburg's contact numbers are (512) 921-4134 and (512) 474-2199. Furthermore, there's 1 email address that belongs to this individual. 2 family members found for Vantilburg.
(512) 474-2199 (Landline), (512) 921-4134 (Cell Phone)
Kees J Vantilburg, 67 Austin, TX
PO Box 27105, Austin, TX, 78755
Resident Since: 2014
Kees Vantilburg from Austin, TX, was born on May 14, 1959, and is now 67 years old. Over the years, Kees has been associated with 1 address. He currently resides at PO Box 27105 in Austin, Texas, 78755. 2 family members found for Vantilburg.
Questions about Kees Vantilburg
Kees Vantilburg currently lives at 613 Oakland Ave, Austin, TX, 78703 and has lived at this address since 2014.
There are two current phone numbers associated with Kees Vantilburg. Try calling Kees Vantilburg’s landline at (512) 474-2199 or reach Kees Vantilburg at (512) 921-4134. The latter is a mobile phone number.
Try reaching out to Kees Vantilburg at [email protected].
The following people are indicated as Kees Vantilburg’s relatives: Kees Vantilburg, Sandra Vantilburg.
Born on May 14, 1959, Kees Vantilburg is or will soon be 67.
A background report is required in order to verify whether Kees Vantilburg has been involved in any criminal activity.