31 90th Pl, Kansas City, MO, 64155
Tom Rose in Missouri 2 Public Records Found
2 people with the name Tom Rose, aged 66 to 66, have been found in Missouri, including Houston, and Kansas City. Locate Rose's birthdays, relatives, neighbors, associates, and property details to confirm the correct person. You may also find their criminal records, social media accounts, and other public data.
Tom J Rose, 66 Kansas City, MO
Resident Since: 2022Year Built: 2007Property Type: Single Family Dwelling UnitProperty Value: $130,000
Tom Rose from Kansas City, MO, was born on August 5, 1960, and is now 66 years old. Tom's address history includes 14 addresses. At the moment, he lives at 31 90th Pl in Kansas City, Missouri, 64155. He has been a resident of the $130,000 home, which was built in 2007, since 2022. The numbers (816) 868-9688 and (816) 413-0521 are registered under Tom Rose's name. Furthermore, there are 4 email addresses that belong to him.
(816) 413-0521 (Landline), (816) 868-9688 (Cell Phone)
Tom Rose Houston, MO
306 Chestnut St, Houston, MO, 65483
Resident Since: 2014Property Type: Single Family Dwelling Unit
According to our records, Tom Rose's phone number is (417) 967-8913. Furthermore, he can be reached at 1 email address.
(417) 967-8913 (Landline)
Questions about Tom J Rose
He currently resides at 31 90th Pl, Kansas City, MO, 64155 and has been a resident there since 2022.
Tom J Rose has changed his address more than once. Before he moved into his current home, he lived at 9721 Lewis Ave, Kansas City, MO, 64157, 12510 Homestead Ln, Olathe, KS, 66061.
Try calling Tom J Rose at (816) 868-9688. This is his current cell phone number. Alternatively, you can reach Tom J Rose on his landline phone at (816) 413-0521.
Use the following email addresses to reach him: [email protected], [email protected], [email protected], or [email protected].
Tom J Rose was born on August 5, 1960. He is about to turn or has already turned 66.
His criminal records may include charges, offenses, offense dates, and other information, if any.