2 Public Records Found

2 people with the name Olivia Parriott, aged 48 to 48, have been found in California, including Oakland, and San Francisco. Locate Parriott's birthdays, relatives, neighbors, associates, and property details to confirm the correct person. You may also find their criminal records, social media accounts, and other public data.

Address History

2453 Wilbur St, Oakland, CA, 94602

Resident Since: 2026Year Built: 1910Property Type: Single Family Dwelling UnitProperty Value: $900

Olivia Parriott, born on July 26 in 1978, now lives in Oakland, CA. 2453 Wilbur St in Oakland, California, 94602 is Olivia's current address. Her address history includes 9 previous residences. She has been a resident of the $900 home, which was built in 1910, since 2026. Olivia Parriott currently owns 5 numbers. They are (510) 479-3827 and (323) 854-3737. Additionally, she has 2 primary email addresses. 3 family members found for Parriott.

Phone Numbers

(323) 654-7792 (Landline), (323) 854-3737 (Cell Phone)

Address History

891 York St, San Francisco, CA, 94110

Resident Since: 2019Property Type: Single Family Dwelling Unit

Olivia Parriott, 48, currently resides in San Francisco, CA. 1 family member is related to Parriott.

Questions about Olivia Firenze Parriott

Olivia Firenze Parriott’s current address is 2453 Wilbur St, Oakland, CA, 94602. She has been a resident there since she moved in 2026.

Her previous home addresses are 2453 Wilbur St, Oakland Park, CA, 8235 Lincoln Ter, Los Angeles, CA.

Olivia Firenze Parriott has two current phone numbers. Try reaching Olivia Firenze Parriott on her landline phone at (323) 654-7792 or call her mobile phone on (323) 854-3737.

Her email addresses are [email protected] or [email protected].

The following people are believed to be related to her: Diane Parriott, James Parriott, Olivia Parriott.

Olivia Firenze Parriott is currently 48. Her exact date of birth is July 26, 1978.

Her criminal records may include charges, offenses, offense dates, and other information, if any.