453 Stouffer Ave, Chambersburg, PA, 17201
Ruby Ocker in Pennsylvania 2 Public Records Found
2 people with the name Ruby Ocker, aged 65 to 82, have been found in Pennsylvania, including Chambersburg. Locate Ocker's birthdays, relatives, neighbors, associates, and property details to confirm the correct person. You may also find their criminal records, social media accounts, and other public data.
Ruby E Ocker, 82 Chambersburg, PA
Resident Since: 2004Property Type: Single Family Dwelling UnitProperty Value: $140,515
Ruby Ocker, born on November 22 in 1943, now lives in Chambersburg, PA. Address history for Ruby includes 7 addresses. Now she lives at 453 Stouffer Ave in Chambersburg, Pennsylvania, 17201. You can call or text Ruby Ocker at (717) 264-7656 and (623) 203-0315, her 2 current phone numbers. Additionally, she owns 2 primary email addresses. 1 family member is related to Ocker.
Ruby F Ocker, 65 Chambersburg, PA
2459 Fisher Rd, Chambersburg, PA, 17202
Resident Since: 2013Property Type: Single Family Dwelling UnitProperty Value: $310,648
Ruby Ocker, age 65, lives in Chambersburg, PA. The numbers (717) 267-1152 and (717) 860-3679 are registered under Ruby Ocker's name. Furthermore, she can be reached at 1 email address. 3 family members are related to Ocker.
(717) 267-1152 (Landline), (717) 860-3679 (Cell Phone)
Questions about Ruby E Ocker
Ruby E Ocker’s current address is 453 Stouffer Ave, Chambersburg, PA, 17201. She has been a resident there since 2004.
Her previous residential addresses are as follows: 132 Kennedy St, Marion, PA, 17235, PO Box 53, Marion, PA, 17235.
You can call Ruby E Ocker’s mobile phone at (623) 203-0315 or reach Ruby E Ocker on her landline phone at (717) 264-7656.
Her email addresses are [email protected] or [email protected].
Public databases identify the following people as her family members: Janet Ocker.
Ruby E Ocker was born on November 22, 1943, so she is about to turn or is already 82.
Her criminal records may include charges, offenses, offense dates, and other information, if any.