5207 Meadowview Dr, Camarillo, CA, 93012
Sandy Hackney
There is 1 person named Sandy Hackney, 65, in California in Camarillo in our database. Locate Hackney's birthday, relatives, neighbors, associates, and property details to get an idea about the person. You may also find their criminal records, social media accounts, and other public data.
Sandy J Hackney, 65 Camarillo, CA
Resident Since: 2008Year Built: 1978Property Type: Single Family Dwelling UnitProperty Value: $419,000
Sandy Hackney from Camarillo, CA, born on January 31 in 1961, is 65 years old. Address history for Sandy includes 11 addresses. Now she lives at 5207 Meadowview Dr in Camarillo, California, 93012. Records show she moved to the property in 2008. The house's estimated value is $419,000 and it was built in 1978. You can call or text Sandy Hackney at (818) 437-0874 and (626) 999-5909, her 3 current phone numbers. Furthermore, there are 7 email addresses that belong to her. 2 family members are related to Hackney.
(626) 999-5909 (Landline), (818) 437-0874 (Cell Phone)
Questions about Sandy J Hackney
Sandy J Hackney lives at 5207 Meadowview Dr, Camarillo, CA, 93012. She has been living at this address since 2008.
Sandy J Hackney has moved more than once. Her previous residential addresses are as follows: 36457 Harold St, Palmdale, CA, 93550, 7049 Vassar Ave, Canoga Park, CA, 91303.
Sandy J Hackney has both landline and mobile phone numbers. Try to call Sandy J Hackney’s landline at (626) 999-5909 or phone her at (818) 437-0874. The latter is her mobile phone number.
You can try to send an email to her at the following email addresses: [email protected], [email protected], [email protected], [email protected], [email protected], [email protected], or [email protected].
Multiple records indicate the following people as her family members: Ronald Hackney, Wanda Hackney.
Sandy J Hackney is approaching or has already turned 65. She was born on January 31, 1961.
Her criminal records may include charges, offenses, offense dates, and other information, if any.