893 Euclaire Ave, Columbus, OH, 43209
John Birkhimer in Ohio 2 Public Records Found
2 people with the name John Birkhimer, aged 72 to 83, have been found in Ohio, including Columbus, and Urbana. Locate Birkhimer's birthdays, relatives, neighbors, associates, and property details to confirm the correct person. You may also find their criminal records, social media accounts, and other public data.
John A Birkhimer, 72 Columbus, OH
Resident Since: 2012Year Built: 1924Property Type: Single Family Dwelling UnitProperty Value: $118,000
John Birkhimer, born on July 10 in 1954, currently resides in Columbus, OH. Since 2012, he has been a resident of the $118,000 property that was constructed in 1924. John Birkhimer's numbers are (614) 551-9810 and (614) 239-9034. Additionally, he owns 2 primary email addresses. 3 family members found for Birkhimer.
(614) 239-9034 (Landline), (614) 551-9810 (Cell Phone)
John M Birkhimer, 83 Urbana, OH
5552 Springfield Urbana Pike, Urbana, OH, 43078
Resident Since: 2012Year Built: 1954Property Type: Single Family Dwelling Unit
John Birkhimer, born on February 11 in 1943, now lives in Urbana, OH. The property was built in 1954. You can call or text John Birkhimer at (937) 484-3078 and (937) 508-9414, his 2 current phone numbers. Additionally, he has 3 primary email addresses.
(937) 484-3078 (Landline), (937) 508-9414 (Cell Phone)
Questions about John A Birkhimer
John A Birkhimer currently resides at 893 Euclaire Ave, Columbus, OH, 43209. He changed his address in 2012.
Please call John A Birkhimer at (614) 551-9810. This is his current cell phone number. Alternatively, you can reach John A Birkhimer on his landline phone at (614) 239-9034.
Contact him at the following email addresses: [email protected] or [email protected].
Our files list the following people as his family members: Carla Birkhimer, Lily Birkhimer, William Birkhimer.
John A Birkhimer is 72 years old and he was born on July 10, 1954.
His criminal records may include charges, offenses, offense dates, and other information, if any.