2 Public Records Found

2 people with the name Jake Autry, aged 33 to 100, have been found in New Mexico, including Edgewood, and Santa Rosa. Locate Autry's birthdays, relatives, neighbors, associates, and property details to confirm the correct person. You may also find their criminal records, social media accounts, and other public data.

Address History

1155 Tejada Rd, Santa Rosa, NM, 88435

Resident Since: 2012Property Type: Single Family Dwelling Unit

Jake Autry from Santa Rosa, NM, was born on September 4, 1926, and is now 100 years old. Jake has been associated with 10 different addresses over the years. 1155 Tejada Rd in Santa Rosa, New Mexico, 88435 is his current address. The numbers (303) 695-4849 and (575) 472-0101 are registered under Jake Autry's name. Additionally, he owns 3 primary email addresses.

Phone Numbers

(303) 695-4849 (Landline), (303) 817-0409 (Cell Phone)

Address History

4 Kiowa Ct, Edgewood, NM, 87015

Resident Since: 2022Year Built: 2008Property Type: Single Family Dwelling UnitProperty Value: $327,000

Jake Autry is 33 and lives in Edgewood, NM. Jake's address history includes 2 addresses. At the moment, he lives at 4 Kiowa Ct in Edgewood, New Mexico, 87015. The $327,000 house was built in the year 2008. He has been living in it since 2022. (505) 384-4179 is Jake Autry's contact number. 2 family members are related to Autry.

Phone Number

(505) 384-4179 (Landline)

Questions about Jake Autry

He lives at 1155 Tejada Rd, Santa Rosa, NM, 88435 and has been a resident there since 2012.

He is known to have lived at 10200 Harvard Ave, Denver, CO, 80231, 2727 Godby Rd, Atlanta, GA, 30349.

You can try reaching Jake Autry on his home phone at (303) 695-4849 or call his mobile phone at (303) 817-0409.

You can try to reach out to him at the following email addresses: [email protected], [email protected], or [email protected].

Jake Autry was born on September 4, 1926. He is 100 years old now.

His criminal records may include charges, offenses, offense dates, and other information, if any.