1167 Mcdonald Hill Rd, Frankfort, OH, 45628
Lori Stanforth
There is 1 person with the name Lori Stanforth in the U.S. They are 53 years old and live in Ohio. Lori Stanforth's information, such as phone numbers, emails, and current and past addresses, may be available on Rew Online. Get access to Lori's birthday, relatives, neighbors, associates, and property details to get an idea about them. You may also find their criminal records, social media accounts, and other public data.
Lori A Stanforth, 53 Frankfort, OH
Resident Since: 2001Year Built: 2002Property Type: Single Family Dwelling UnitProperty Value: $15,000
Lori Stanforth, born on November 26 in 1972, currently resides in Frankfort, OH. Over the years, Lori has been associated with 5 addresses. She currently resides at 1167 Mcdonald Hill Rd in Frankfort, Ohio, 45628. She moved to the property, which is valued at $15,000, in 2001. The house was built in 2002. Lori Stanforth's contact numbers are (740) 253-2207 and (740) 998-6628. Furthermore, she can be reached at 1 email address. Our records show 3 family members for Stanforth.
(740) 998-6628 (Landline), (740) 253-2207 (Cell Phone)
Questions about Lori A Stanforth
She resides at 1167 Mcdonald Hill Rd, Frankfort, OH, 45628 and has been a resident there since 2001.
Lori A Stanforth has changed her address several times. Before she moved to her current place, she used to live at the following addresses: 1167 Mcdonald Rd, Chillicothe, OH, 45601, 110 Shawnee St, Bainbridge, OH, 45612.
You can call Lori A Stanforth’s landline phone at (740) 998-6628 or ring her cell phone at (740) 253-2207.
[email protected] is the email address associated with her.
Multiple records list the following people as her family: Andrew Stanforth, Darrin Stanforth, Laci Stanforth.
Lori A Stanforth was born on November 26, 1972. She is 53 or will soon be.
She is known to have a career associated with the following field/occupation: cosmetologist.
Her criminal records may include charges, offenses, offense dates, and other information, if any.