2 Public Records Found

There are 2 people with the name Len Farrior, aged 72 to 92, in the U.S. Len Farrior's information, such as phone numbers, emails, and current and past addresses from 1 state, including California, have been found on Rew Online. Get access to Len's birthdays, relatives, neighbors, associates, and property details to verify the right person. You may also find their criminal records, social media accounts, and other public data.

Address History

24804 Manton Rd, Colton, CA, 92324

Resident Since: 2012Year Built: 1987Property Type: Single Family Dwelling UnitProperty Value: $8,000

Len Farrior, born on March 14 in 1954, currently resides in Colton, CA. The $8,000 house was built in the year 1987. He has been living in it since 2012. To get in touch with Len Farrior, you can call him at (951) 818-1904 and (909) 370-4324. Additionally, he has 2 active email addresses. 2 family members found for Farrior.

Phone Numbers

(909) 370-4324 (Landline), (951) 818-1904 (Cell Phone)

Address History

6062 Oliva Ave, Lakewood, CA, 90712

Resident Since: 2019Year Built: 1947Property Type: Single Family Dwelling UnitProperty Value: $362,691

Len Farrior, 92, is a current resident of Lakewood, CA. He has been a resident of the $362,691 home, which was built in 1947, since 2019. (562) 633-1655 is Len Farrior's contact number. 4 family members are related to Farrior.

Phone Number

(562) 633-1655 (Landline)

Questions about Len Farrior

He lives at 24804 Manton Rd, Colton, CA, 92324 and has lived there since 2012.

Len Farrior has two current phone numbers. You can try to reach Len Farrior on his landline phone at (909) 370-4324 or call his mobile phone on (951) 818-1904.

Use the following email addresses to contact him: [email protected] or [email protected].

Our system has identified the following people as his relatives: Doris Farrior, S Farrior.

Len Farrior was born on March 14, 1954, so now he is 72 years old.

His criminal records may include charges, offenses, offense dates, and other information, if any.