8921 267th East Ave, Broken Arrow, OK, 74014
David Devries
1 person with the name David Devries, who is 61 years old, lives in Broken-Arrow, OK. Devries's information, such as cell and landline numbers, emails, and current and past addresses, have been found on Rew Online. In addition, you can check whether their birthday, family members, neighbors, social media accounts, criminal records, and other public data are available in our database.
David J Devries, 61 Broken Arrow, OK
Resident Since: 2026Year Built: 1999Property Type: Single Family Dwelling UnitProperty Value: $249
David Devries, who currently lives in Broken Arrow, OK, was born on November 24 in 1964. David has been associated with 11 different addresses over the years. 8921 267th East Ave in Broken Arrow, Oklahoma, 74014 is his current address. The $249 house was built in the year 1999. He has been living in it since 2026. (918) 357-9925 and (918) 605-2252 are David Devries's contact numbers. Furthermore, there's 1 email address that belongs to him. Devries has 4 family members.
(918) 357-9925 (Landline), (918) 605-2252 (Cell Phone)
Questions about David J Devries
His current residential address is 8921 267th East Ave, Broken Arrow, OK, 74014 and has not changed since 2026.
David J Devries has changed his address more than once. Before he moved into his current home, he used to live at 8921 267th Ave, Broken Arrow, OK, 74014, 905 Ridgecrest Ave, Stillwater, OK, 74075.
You can try to call David J Devries’s mobile phone at (918) 605-2252 or reach David J Devries on his landline phone at (918) 357-9925.
You can send him an email at [email protected].
Our records identify the following people as his relatives: Dick Devries, Kenton Devries, Sierra Devries, Teresa Devries.
David J Devries was born on November 24, 1964, so he is currently 61.
It is believed that at some point he was associated with the following professional field/occupation: manager/marketing manager.
Any criminal record related to him will be revealed through a comprehensive background report.