There is 1 person with the name Jacki Amick in the U.S. They are 61 years old and live in Pennsylvania. Jacki Amick's information, such as phone numbers, emails, and current and past addresses, may be available on Rew Online. Get access to Jacki's birthday, relatives, neighbors, associates, and property details to get an idea about them. You may also find their criminal records, social media accounts, and other public data.

Address History

1724 Ridge Rd, New Entrprise, PA, 16664

Resident Since: 2026Year Built: 2001Property Type: Single Family Dwelling UnitProperty Value: $175

Jacki Amick from New Entrprise, PA, was born on November 18, 1964, and is now 61 years old. Jacki has been associated with 9 different addresses over the years. 1724 Ridge Rd in New Entrprise, Pennsylvania, 16664 is their current address. The $175 house was built in the year 2001. This person has been living in it since 2026. To get in touch with Jacki Amick, you can call them at (814) 330-0690 and (814) 766-3119. Additionally, this individual owns 3 primary email addresses. Amick has 5 family members.

Phone Numbers

(814) 766-3119 (Landline), (814) 330-0690 (Cell Phone)

Questions about Jacki M Amick

Jacki M Amick lives at 1724 Ridge Rd, New Entrprise, PA, 16664.

Jacki M Amick is known to have lived at the following addresses: 1724 Ridge Rd, New Enterprise, PA, 16664, 115 Dovetail Ln, New Enterprise, PA, 16664.

The current landline phone number for Jacki M Amick is (814) 766-3119. The cell phone number associated with Jacki M Amick is (814) 330-0690.

Reach out to Jacki M Amick at the following email addresses: [email protected], [email protected], or [email protected].

Our files list the following people as the relatives of Jacki M Amick: Brian Amick, Joel Amick, Justin Amick, Margaret Amick, Ray Amick.

Jacki M Amick is 61 years old and was born on November 18, 1964.

Jacki M Amick is believed to have a career associated with the following field/employment: homemaker.

A background check may reveal any criminal records Jacki Amick may have.